-4p^2+4000p=0

Solution for -4p^2+4000p=0 equation:

-4p^2+4000p=0

a = -4; b = 4000; c = 0;
Δ = b2-4ac
Δ = 40002-4·(-4)·0
Δ = 16000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16000000}=4000$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4000)-4000}{2*-4}=\frac{-8000}{-8}
=+1000
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4000)+4000}{2*-4}=\frac{0}{-8}
=0
$